1956 AMC 12 Problem 42

Attempt Problem 42 of the 1956 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1956 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

42.

The equation x+4−x−3+1=0\sqrt{x+4}-\sqrt{x-3}+1=0 has:
no root
one real root
one real root and one imaginary root
two imaginary roots
two real roots
Answer: A
Concepts:radical equationinequalitiesreal domain
Small hint:
For real square roots the domain requires x≥3x\ge3
Big hint:
On that domain, compare x+4\sqrt{x+4} directly with x−3\sqrt{x-3}
Solution:
For a real solution, x≥3.x\ge3. Then x+4>x−3,x+4>x-3, so x+4>x−3. \sqrt{x+4}>\sqrt{x-3}. Consequently x+4−x−3+1>1,\sqrt{x+4}-\sqrt{x-3}+1>1, and it cannot equal zero. The original equation is a real radical expression, so nonreal roots are outside its domain.
The correct answer is A.
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