1959 AMC 12 Problem 42

Attempt Problem 42 of the 1959 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1959 AMC 12 solutions, or check the answer key.

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42.

Given three positive integers a,a, b,b, and c.c. Their greatest common divisor is D;D; their least common multiple is M.M. Then, which two of the following statements are true?

(1)(1) The product MDMD cannot be less than abc.abc.

(2)(2) The product MDMD cannot be greater than abc.abc.

(3)(3) MDMD equals abcabc if and only if a,a, b,b, cc are each prime.

(4)(4) MDMD equals abcabc if and only if a,a, b,b, cc are relatively prime in pairs. (This means: no two have a common factor greater than 1.1.)

1,1, 22

1,1, 33

1,1, 44

2,2, 33

2,2, 44

Answer: E
Concepts:greatest common divisorleast common multipleprime factorization
Difficulty rating: 1790
Small Hint:

For one prime, order its exponents in a,b,ca,b,c as uvwu\le v\le w

Big Hint:

Compare the exponent u+wu+w in MDMD with the exponent u+v+wu+v+w in abcabc

Solution:

For any prime, let its exponents in a,b,ca,b,c be uvw.u\le v\le w. Its exponent in MDMD is u+w,u+w, while its exponent in abcabc is u+v+w.u+v+w. Thus MDabc,MD\le abc, proving statement (2).(2). Equality holds exactly when v=0v=0 for every prime, meaning no prime divides two of a,b,c.a,b,c. That is precisely pairwise relative primality, proving statement (4).(4).

Therefore, the correct answer is E.

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Problem 42 in Other Years

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