1956 AMC 12 Problem 22

Attempt Problem 22 of the 1956 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1956 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

22.

Jones covered a distance of 5050 miles on his first trip. On a later trip he traveled 300300 miles while going three times as fast. His new time compared with the old time was:
three times as much
twice as much
the same
half as much
a third as much
Answer: B
Concepts:rate-time-distanceproportional reasoning
Small hint:
Write each travel time as distance divided by speed
Big hint:
If the old speed is v,v, compare 50v\frac{50}{v} with 3003v\frac{300}{3v}
Solution:
If the first speed was v,v, the old time was 50v.\frac{50}{v}. The later time was 3003v=100v=2(50v). \frac{300}{3v}=\frac{100}{v}=2\left(\frac{50}{v}\right). Thus the new time was twice the old time.
The correct answer is B.
LIVE by Po-Shen Loh
Programs

LIVE Classes

Self-Paced Classes

Stars

Scholarship

About Us

Who Is Po-Shen Loh?

Email Contact

Newsletter

Jobs

Become a Star

For a more Thought Full world.

© 2026 Expii, Inc.