1954 AMC 12 Problem 38

Attempt Problem 38 of the 1954 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1954 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

38.

If log2=0.3010\log 2=0.3010 and log3=0.4771,\log 3=0.4771, the value of xx when 3x+3=1353^{x+3}=135 is approximately:

55

1.471.47

1.671.67

1.781.78

1.631.63

Answer: B
Concepts:logarithmexponentestimation
Difficulty rating: 1340
Small Hint:

Divide by 333^3 to obtain 3x=53^x=5

Big Hint:

Use log5=1log2\log5=1-\log2 and divide by log3\log3

Solution:

The equation reduces to 3x=5,3^x=5, so x=log5log3=1log2log3=0.69900.47711.47. \begin{aligned} x&=\frac{\log5}{\log3}\\ &=\frac{1-\log2}{\log3}\\ &=\frac{0.6990}{0.4771}\\ &\approx1.47. \end{aligned}

Thus, the correct answer is B.

← Problem 37#37
Full Exam

Problem 38 in Other Years

1950 AMC 12 · 1951 AMC 12 · 1952 AMC 12 · 1953 AMC 12 · 1955 AMC 12 · 1956 AMC 12 · 1957 AMC 12 · 1958 AMC 12 · 1959 AMC 12 · 1960 AMC 12 · 1961 AMC 12 · 1962 AMC 12 · 1963 AMC 12 · 1964 AMC 12 · 1965 AMC 12 · 1966 AMC 12 · 1967 AMC 12