1953 AMC 12 Problem 35

Attempt Problem 35 of the 1953 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1953 AMC 12 solutions, or check the answer key.

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35.

If f(x)=x(x−1)2,f(x)=\dfrac{x(x-1)}2, then f(x+2)f(x+2) equals:
f(x)+f(2)f(x)+f(2)
(x+2)f(x)(x+2)f(x)
x(x+2)f(x)x(x+2)f(x)
xf(x)x+2\dfrac{xf(x)}{x+2}
(x+2)f(x+1)x\dfrac{(x+2)f(x+1)}x
Answer: E
Concepts:function notationalgebraic identity
Small hint:
Write explicit formulas for both f(x+2)f(x+2) and f(x+1)f(x+1)
Big hint:
The factor xx in f(x+1)=x(x+1)2f(x+1)=\frac{x(x+1)}{2} cancels in one choice
Solution:
Directly, f(x+2)=(x+2)(x+1)2. f(x+2)=\frac{(x+2)(x+1)}2. Also f(x+1)=x(x+1)2,f(x+1)=\frac{x(x+1)}{2}, so (x+2)f(x+1)x=(x+2)(x+1)2. \begin{gathered} \frac{(x+2)f(x+1)}x\\ =\frac{(x+2)(x+1)}2. \end{gathered}
Thus, the correct answer is E.
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