1950 AMC 12 Problem 35
Attempt Problem 35 of the 1950 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1950 AMC 12 solutions, or check the answer key.
All problems are used with official legal permission of the Mathematical Association of America (MAA).
35.
In triangle inches, inches, inches. The radius of the inscribed circle is:
in
in
in
in
None of these
Answer: B
Small Hint:
The side lengths form a right triangle
Big Hint:
For a right triangle with legs and hypotenuse the inradius is
Solution:
Since the triangle is right. Its area is and its semiperimeter is Using the inradius, in inches, is
Thus, the correct answer is B.
Problem 35 in Other Years
1951 AMC 12 · 1952 AMC 12 · 1953 AMC 12 · 1954 AMC 12 · 1955 AMC 12 · 1956 AMC 12 · 1957 AMC 12 · 1958 AMC 12 · 1959 AMC 12 · 1960 AMC 12 · 1961 AMC 12 · 1962 AMC 12 · 1963 AMC 12 · 1964 AMC 12 · 1965 AMC 12 · 1966 AMC 12 · 1967 AMC 12 · 1968 AMC 12 · 1969 AMC 12 · 1970 AMC 12 · 1971 AMC 12 · 1972 AMC 12 · 1973 AMC 12