1956 AMC 12 Problem 35

Attempt Problem 35 of the 1956 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1956 AMC 12 solutions, or check the answer key.

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35.

A rhombus is formed by two radii and two chords of a circle whose radius is 1616 feet. The area of the rhombus in square feet is:

128128

1283128\sqrt3

256256

512512

5123512\sqrt3

Answer: B
Concepts:rhombuschord lengthcentral anglearea
Difficulty rating: 1880
Small Hint:

Every side of the rhombus has length 16,16, so each chord equals the radius

Big Hint:

A chord equal to the radius subtends a 6060^\circ central angle; use s2sinθs^2\sin\theta

Solution:

All four sides of the rhombus equal the circle’s radius, 16.16. A chord of length equal to the radius forms an equilateral triangle with the two radii to its endpoints, so the included central angle is 60.60^\circ. Therefore the rhombus has area 162sin60=25632=1283. \begin{aligned} 16^2\sin60^\circ &=256\cdot\frac{\sqrt3}{2}\\ &=128\sqrt3. \end{aligned}

Thus, the correct answer is B.

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