1953 AMC 12 Problem 34

Attempt Problem 34 of the 1953 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1953 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

34.

If one side of a triangle is 1212 inches and the opposite angle is 3030 degrees, then the diameter of the circumscribed circle is:
1818 inches
3030 inches
2424 inches
2020 inches
none of these
Answer: C
Concepts:extended law of sinescircumcircletriangle
Small hint:
Relate a side, its opposite angle, and the circumdiameter
Big hint:
The extended law of sines gives d=asin⁡Ad=\frac{a}{\sin A}
Solution:
By the extended law of sines, the circumdiameter is d=12sin⁡30∘=1212=24 d=\frac{12}{\sin30^\circ}=\frac{12}{\frac{1}{2}}=24 inches.
Thus, the correct answer is C.
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