2024 AMC 10B Problem 22

Attempt Problem 22 of the 2024 AMC 10B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2024 AMC 10B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

22.

A group of 1616 people will be partitioned into 44 indistinguishable 44-person committees. Each committee will have one chairperson and one secretary. The number of different ways to make these assignments can be written as 3rM,3^r M, where rr and MM are positive integers and MM is not divisible by 3.3. What is r?r?
55
66
77
88
99
Answer: A
Concepts:combinationsLegendre’s Formulaprime factorization
Small hint:
The number of ways is 16!(4!)4⋅4!⋅(4⋅3)4,\dfrac{16!}{(4!)^4 \cdot 4!} \cdot (4 \cdot 3)^4, the partition count times chair/secretary choices per committee
Big hint:
Count factors of 33 in each piece using Legendre’s formula on 16!16! and 4!4!
Solution:
Split 1616 people into 44 indistinguishable groups of 44 in 16!(4!)4 4!\dfrac{16!}{(4!)^4 \, 4!} ways, then each committee picks a chairperson and a secretary in 4⋅3=124 \cdot 3 = 12 ways, a factor of 124.12^4. Now count factors of 3.3. In 16!16! there are ⌊163⌋+⌊169⌋=6;\lfloor \frac{16}{3} \rfloor + \lfloor \frac{16}{9} \rfloor = 6; the denominator (4!)4 4!(4!)^4 \, 4! contributes 4⋅1+1=5;4 \cdot 1 + 1 = 5; and 12412^4 contributes 4.4. The exponent is 6−5+4=5,6 - 5 + 4 = 5, so r=5.r = 5. Therefore, the answer is A.
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