2023 AMC 10B Problem 3

Attempt Problem 3 of the 2023 AMC 10B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2023 AMC 10B solutions, or check the answer key.

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3.

A 33-44-55 right triangle is inscribed in circle A,A, and a 55-1212-1313 right triangle is inscribed in circle B.B. What is the ratio of the area of circle AA to the area of circle B?B?

925\dfrac{9}{25}

19\dfrac{1}{9}

15\dfrac{1}{5}

25169\dfrac{25}{169}

425\dfrac{4}{25}

Answer: D
Concepts:circumcircle, circumcenter, and circumradiusright trianglearea ratio
Difficulty rating: 1080
Solution:

The hypotenuse of a right triangle is a diameter of the circle around it. So circle AA has diameter 55 and circle BB has diameter 13.13. Areas scale as the square of that, giving (513)2=25169.\left(\frac{5}{13}\right)^2 = \frac{25}{169}. Thus, D is the correct answer.

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