2023 AMC 10B Problem 24

Attempt Problem 24 of the 2023 AMC 10B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2023 AMC 10B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

24.

What is the perimeter of the boundary of the region consisting of all points which can be expressed as (2u−3w, v+4w)(2u - 3w,\ v + 4w) with 0≤u≤1,0 \le u \le 1, 0≤v≤1,0 \le v \le 1, and 0≤w≤1?0 \le w \le 1?
10310\sqrt{3}
1313
1212
1818
1616
Answer: E
Concepts:coordinate geometryvectorperimeter
Small hint:
Fixing w,w, the pair (u,v)(u, v) sweeps a 2×12 \times 1 rectangle; varying ww slides it along (−3,4)(-3, 4)
Big hint:
The boundary is a hexagon with opposite side lengths 2,1,2, 1, and (−3)2+42\sqrt{(-3)^2+4^2}
Solution:
Fix w.w. As u,vu, v sweep [0,1]2,[0, 1]^2, the point (2u−3w, v+4w)(2u - 3w,\ v + 4w) fills a 2×12 \times 1 axis-aligned rectangle with lower-left corner (−3w,4w).(-3w, 4w). As ww runs from 00 to 1,1, this rectangle slides along the vector (−3,4),(-3,4), whose length is 5.5. The swept region is a centrally symmetric hexagon. Its opposite pairs of sides have lengths 2,1,2, 1, and 5,5, inherited from the two sides of the rectangle and the sliding segment. Therefore its perimeter is 2(2+1+5)=16.2(2+1+5)=16. Therefore, the answer is E.
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