2021 AMC 10A Fall Problem 16

Attempt Problem 16 of the 2021 AMC 10A Fall below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2021 AMC 10A Fall solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

16.

Consider the function
f(x)=∣⌊x⌋∣−∣⌊1−x⌋∣f(x) = |\lfloor x \rfloor| - |\lfloor 1 - x \rfloor|
Its graph is symmetric about which of the following? (Here ⌊x⌋\lfloor x \rfloor is the greatest integer not exceeding x.x.)
the yy-axis
the line x=1x=1
the origin
the point (12,0)\left(\dfrac{1}{2},0\right)
the point (1,0)(1,0)
Answer: D
Concepts:floor and ceiling functionssymmetry (algebra)
Small hint:
Compare f(1−x)f(1-x) with f(x)f(x)
Big hint:
The relation is point symmetry, not line symmetry
Solution:
For every real x,x, f(1−x)=∣⌊1−x⌋∣−∣⌊x⌋∣=−f(x). \begin{aligned} &f(1-x)=|\lfloor 1-x\rfloor| \\ &\quad {}-|\lfloor x\rfloor|=-f(x). \end{aligned}
Equivalently, replacing xx by 12+t\frac{1}{2}+t gives f ⁣(12−t)=−f ⁣(12+t).f\!\left(\frac{1}{2}-t\right)=-f\!\left(\frac{1}{2}+t\right). This is point symmetry about (12,0).\left(\frac{1}{2},0\right).
Thus, D is the correct answer.
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