2021 AMC 10A Spring Problem 3

Attempt Problem 3 of the 2021 AMC 10A Spring below, then check your answer against the video solution and professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2021 AMC 10A Spring solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

3.

The sum of two natural numbers is 17,402.17{,}402. One of the two numbers is divisible by 10.10. If the units digit of that number is erased, the other number is obtained. What is the difference of these two numbers?
10,27210{,}272
11,70011{,}700
13,36213{,}362
14,23814{,}238
15,42615{,}426
Answer: D
Concepts:place valuelinear equation
Small hint:
If deleting the final zero gives the other number, the larger number is ten times the smaller one
Big hint:
Use the sum to find the smaller number first
Video solution:
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Written solution:
Let xx and yy be the two numbers. WLOG, let xx be divisible by 10.10. Then the units digit of xx is 0.0.
If we erase the units digit, then we are essentially dividing xx by 10.10. The problem statement also gives us that x10=y.\dfrac{x}{10} = y.
Therefore, x10+x=17,40211x10=17,402x=15,820. \begin{aligned} \dfrac{x}{10} + x &= 17,402 \\ \dfrac{11x}{10} &= 17,402 \\ x &= 15,820. \end{aligned} Then x−x10=14,238. x - \dfrac{x}{10} = 14,238.
Thus, D is the correct answer.
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