2021 AMC 10A Spring Problem 16

Attempt Problem 16 of the 2021 AMC 10A Spring below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2021 AMC 10A Spring solutions, or check the answer key.

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16.

In the following list of numbers, the integer nn appears nn times in the list for 1n200.1\leq n\leq200. 1,2,2,3,3,3,4,4,4,4,,200,200,,200 \begin{aligned} &1,2,2,3,3,3,4,4,4,4,\ldots,\\ &200,200,\ldots,200 \end{aligned} What is the median of the numbers in this list?

100.5100.5

134134

142142

150.5150.5

167167

Answer: C
Concepts:median (data)triangular number
Difficulty rating: 1420
Solution:

The list contains 1+2++200=2002012=20100 \begin{aligned} 1+2+\cdots+200&=\frac{200\cdot201}{2}\\ &=20100 \end{aligned} entries, so its two middle positions are 1005010050 and 10051.10051.

There are 1411422=10011\frac{141\cdot142}{2}=10011 entries through the last 141,141, and 1421432=10153\frac{142\cdot143}{2}=10153 entries through the last 142.142. Thus both middle entries are 142,142, so the median is 142.142.

Thus, C is the correct answer.

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