2021 AMC 10A Spring Problem 16

Attempt Problem 16 of the 2021 AMC 10A Spring below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2021 AMC 10A Spring solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

16.

In the following list of numbers, the integer nn appears nn times in the list for 1≤n≤200.1\leq n\leq200. 1,2,2,3,3,3,4,4,4,4,…,200,200,…,200 \begin{aligned} &1,2,2,3,3,3,4,4,4,4,\ldots,\\ &200,200,\ldots,200 \end{aligned} What is the median of the numbers in this list?
100.5100.5
134134
142142
150.5150.5
167167
Answer: C
Concepts:median (data)triangular number
Small hint:
The list has 1+2+⋯+2001+2+\cdots+200 entries
Big hint:
Locate the two middle positions using triangular numbers
Solution:
The list contains 1+2+⋯+200=200⋅2012=20100 \begin{aligned} 1+2+\cdots+200&=\frac{200\cdot201}{2}\\ &=20100 \end{aligned} entries, so its two middle positions are 1005010050 and 10051.10051.
There are 141⋅1422=10011\frac{141\cdot142}{2}=10011 entries through the last 141,141, and 142⋅1432=10153\frac{142\cdot143}{2}=10153 entries through the last 142.142. Thus both middle entries are 142,142, so the median is 142.142.
Thus, C is the correct answer.
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