2019 AMC 10B Problem 13

Attempt Problem 13 of the 2019 AMC 10B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2019 AMC 10B solutions, or check the answer key.

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13.

What is the sum of all real numbers xx for which the median of the numbers 4,6,8,17,4,6,8,17, and xx is equal to the mean of those five numbers?

5 -5

0 0

5 5

154 \dfrac{15}{4}

354 \dfrac{35}{4}

Answer: A
Concepts:meanmedian (data)casework
Difficulty rating: 1490
Solution:

The mean is 7+x57+\frac{x}{5}. If x<6x<6, the median is 66, so 7+x5=67+\frac{x}{5}=6 gives the valid value x=5x=-5.

If 6x86\le x\le8, the median is xx, but 7+x5=x7+\frac{x}{5}=x gives x=354x=\frac{35}{4}, outside this interval. If x>8x>8, the median is 88, but 7+x5=87+\frac{x}{5}=8 gives x=5x=5, again outside the required range.

Therefore, the only possible xx is 5,-5, making the sum 5.-5.

Thus, the answer is A .

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