2018 AMC 10B Problem 3

Attempt Problem 3 of the 2018 AMC 10B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2018 AMC 10B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

3.

In the expression (x‾×x‾)+(x‾×x‾)(\underline{\phantom{x}} \times \underline{\phantom{x}}) + (\underline{\phantom{x}} \times \underline{\phantom{x}}) each blank is to be filled in with one of the digits 1,1, 2,2, 3,3, or 4,4, with each digit being used once. How many different values can be obtained?
22
33
44
66
2424
Answer: B
Concepts:basic countingsystematic listing
Small hint:
Neither multiplication nor the final addition depends on order, so only the way the four digits are split into two pairs matters
Big hint:
List the three ways to split {1,2,3,4}\{1,2,3,4\} into two pairs
Solution:
Order inside a product doesn’t matter, and neither does the order we add the two products. So all that matters is how the four digits split into two pairs. There are three splits: 1⋅2+3⋅4=14,1\cdot2 + 3\cdot4 = 14, 1⋅3+2⋅4=11,1\cdot3 + 2\cdot4 = 11, and 1⋅4+2⋅3=10.1\cdot4 + 2\cdot3 = 10. That’s 33 different values. Thus, B is the correct answer.
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