2018 AMC 10A Problem 16

Attempt Problem 16 of the 2018 AMC 10A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2018 AMC 10A solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

16.

Right triangle ABCABC has leg lengths AB=20AB=20 and BC=21.BC=21. Including AB‾\overline{AB} and BC‾,\overline{BC}, how many line segments with integer length can be drawn from vertex BB to a point on hypotenuse AC‾?\overline{AC}?
55
88
1212
1313
1515
Answer: D
Concepts:right trianglealtitudecounting integers in a range
Small hint:
Find the altitude from BB to the hypotenuse
Big hint:
Integer-length segments occur in symmetric pairs around the altitude
Solution:
Let PP be the foot of the altitude from BB to AC‾.\overline{AC}. The Pythagorean Theorem gives AC=29.AC=29. Computing the area in two ways gives 29⋅PB2=20⋅212,\dfrac{29\cdot PB}{2}=\dfrac{20\cdot21}{2}, so PB=42029,PB=\dfrac{420}{29}, which lies between 1414 and 15.15.
As the endpoint moves from AA to P,P, its distance from BB decreases continuously from 2020 to PB.PB. Thus there is one segment of each integer length 15,16,17,18,19,20.15,16,17,18,19,20. As the endpoint moves from PP to C,C, the distance increases continuously from PBPB to 21,21, giving one segment of each integer length 15,16,17,18,19,20,21.15,16,17,18,19,20,21. These are 6+7=136+7=13 distinct segments.
Thus, D is the correct answer.
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