2017 AMC 10B Problem 8

Attempt Problem 8 of the 2017 AMC 10B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2017 AMC 10B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

8.

Points A(11,9)A(11, 9) and B(2,−3)B(2, -3) are vertices of △ABC\triangle ABC with AB=AC.AB=AC. The altitude from AA meets the opposite side at D(−1,3).D(-1, 3). What are the coordinates of point C?C?
(−8,9)(-8, 9)
(−4,8)(-4, 8)
(−4,9)(-4, 9)
(−2,3)(-2, 3)
(−1,0)(-1, 0)
Answer: C
Concepts:coordinate geometrymidpointisosceles triangle
Small hint:
In an isosceles triangle, the altitude from the vertex also bisects the base
Big hint:
Use DD as the midpoint of BCBC
Solution:
Since AB=AC,AB=AC, the altitude from AA also bisects the base BC.BC. Therefore, DD is the midpoint of BC.BC. If C=(x,y),C=(x,y), then we have x+22=−1,\frac{x+2}2 = -1,y−32=3.\frac{y-3}2=3. As such, C=(x,y)=(−4,9).C=(x,y)=(-4,9).
Thus, the correct answer is C .
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