2017 AMC 10B Problem 4

Attempt Problem 4 of the 2017 AMC 10B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2017 AMC 10B solutions, or check the answer key.

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4.

Suppose that xx and yy are nonzero real numbers such that 3x+yx3y=2.\frac{3x+y}{x-3y}=-2. What is the value of x+3y3xy?\frac{x+3y}{3x-y}?

3-3

1-1

11

22

33

Answer: D
Concepts:rational equationalgebraic manipulation
Difficulty rating: 900
Solution:

Given that 3x+yx3y=2,\frac{3x+y}{x-3y}=-2, we can multiply by the denominator to get 3x+y=6y2x.3x+y = 6y-2x. Solving, we can see that x=y.x=y.

Therefore, x+3y3xy=x+3x3xx=2.\frac{x+3y}{3x-y} = \frac{x+3x}{3x-x}=2.

Thus, the correct answer is D .

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