2016 AMC 10B Problem 5

Attempt Problem 5 of the 2016 AMC 10B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2016 AMC 10B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

5.

The mean age of Amanda’s 44 cousins is 8,8, and their median age is 5.5. What is the sum of the ages of Amanda’s youngest and oldest cousins?
 13 \ 13
 16 \ 16
 19 \ 19
 22 \ 22
 25 \ 25
Answer: D
Concepts:meanmedian (data)
Small hint:
The total age is 4⋅84\cdot8
Big hint:
The two middle ages sum to 1010
Solution:
The total of the four cousin ages is 4⋅8=324\cdot8=32. Since the median is 55, the two middle ages have average 55, so their sum is 1010.
Therefore the youngest and oldest ages sum to 32−10=2232-10=22.
Thus, the correct answer is D.
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