2016 AMC 10B Problem 3

Attempt Problem 3 of the 2016 AMC 10B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2016 AMC 10B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

3.

Let x=−2016.x=-2016. What is the value of ∣∣∣x∣−x∣−∣x∣∣−x?\Bigg\vert\Big\vert |x|-x\Big\vert-|x|\Bigg\vert-x?
 −2016 \ -2016
 0 \ 0
 2016 \ 2016
 4032 \ 4032
 6048 \ 6048
Answer: D
Concepts:absolute value
Small hint:
For x<0x<0, ∣x∣=−x|x|=-x
Big hint:
Evaluate the absolute values from the inside outward
Solution:
Since x=−2016<0,x=-2016<0, we have ∣x∣=2016.|x|=2016. Thus ∣x∣−x=2016−(−2016)=4032, \begin{aligned} |x|-x&=2016-(-2016) \\ &=4032, \end{aligned} so the innermost absolute value is 4032.4032. Therefore the full expression is ∣4032−2016∣+2016=4032.|4032-2016|+2016=4032.
Thus, the correct answer is D .
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