2016 AMC 10A Problem 13

Attempt Problem 13 of the 2016 AMC 10A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2016 AMC 10A solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

13.

Five friends sat in a movie theater in a row containing 55 seats, numbered 11 to 55 from left to right. (The directions "left" and "right" are from the point of view of the people as they sit in the seats.)

During the movie Ada went to the lobby to get some popcorn. When she returned, she found that Bea had moved two seats to the right, Ceci had moved one seat to the left, and Dee and Edie had switched seats, leaving an end seat for Ada. In which seat had Ada been sitting before she got up?

11

22

33

44

55

Answer: B
Concepts:logical deductioninvariant
Difficulty rating: 1420
Solution:

The sum of the occupied seat numbers is 1+2+3+4+5=151+2+3+4+5=15 both before and after the moves. Dee and Edie merely switch seats, so their combined displacement is 0.0. Bea's displacement is +2,+2, and Ceci's is 1.-1. Therefore Ada's displacement must be 1-1 so that the total displacement is 0.0.

Ada returns to an end seat. Since she moves one seat left, she must move from seat 22 to seat 1.1.

Thus, the correct answer is B .

← Problem 12#12
Full Exam

Problem 13 in Other Years