2015 AMC 10B Problem 17

Attempt Problem 17 of the 2015 AMC 10B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2015 AMC 10B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

17.

The centers of the faces of the right rectangular prism shown below are joined to create an octahedron. What is the volume of this octahedron?
7512 \dfrac{75}{12}
10 10
12 12
102 10\sqrt{2}
15 15
Answer: B
Concepts:polyhedronpyramidvolume
Small hint:
View the octahedron as two pyramids with a central rhombus base
Big hint:
The base rhombus has diagonals 44 and 55
Solution:
The octahedron can be viewed as two congruent pyramids whose shared base is the rhombus through the centers of the four side faces. This rhombus has diagonals 44 and 55, so its area is 12⋅4⋅5=10\frac12\cdot4\cdot5=10.
Each pyramid has height 32\frac32, half the prism’s height. Thus the total volume is 2⋅13⋅10⋅32=10.2\cdot\frac13\cdot10\cdot\frac32=10.
Thus, the correct answer is B.
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