2015 AMC 10A Problem 7

Attempt Problem 7 of the 2015 AMC 10A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2015 AMC 10A solutions, or check the answer key.

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7.

How many terms are in the arithmetic sequence 13,13, 16,16, 19,19, ,\dotsc, 70,70, 73?73?

2020

2121

2424

6060

6161

Answer: B
Concepts:arithmetic sequence
Difficulty rating: 870
Solution:

Recall that the nnth term of an arithmetic sequence is a+d(n1),a + d(n - 1), where aa is the first term and dd is the common difference.

For us, a=13a = 13 and d=3.d = 3. Plugging these in, we get that 73=13+3(n1)20=n1n=21.\begin{aligned} 73 &= 13 + 3(n - 1) \\ 20&= n - 1 \\ n &= 21. \end{aligned} Thus, B is the correct answer.

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