2015 AMC 10A Problem 7

Attempt Problem 7 of the 2015 AMC 10A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2015 AMC 10A solutions, or check the answer key.

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7.

How many terms are in the arithmetic sequence 13,13, 16,16, 19,19, …,\dotsc, 70,70, 73?73?
2020
2121
2424
6060
6161
Answer: B
Concepts:arithmetic sequence
Small hint:
Use the first term, last term, and common difference
Big hint:
Count intervals, then add one endpoint
Solution:
Recall that the nnth term of an arithmetic sequence is a+d(n−1),a + d(n - 1), where aa is the first term and dd is the common difference.
For us, a=13a = 13 and d=3.d = 3. Plugging these in, we get that 73=13+3(n−1)20=n−1n=21.\begin{aligned} 73 &= 13 + 3(n - 1) \\ 20&= n - 1 \\ n &= 21. \end{aligned} Thus, B is the correct answer.
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