2015 AMC 10A Problem 12

Attempt Problem 12 of the 2015 AMC 10A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2015 AMC 10A solutions, or check the answer key.

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12.

Points (π,a)(\sqrt{\pi}, a) and (π,b)(\sqrt{\pi}, b) are distinct points on the graph of y2+x4=2x2y+1.y^2 + x^4 = 2x^2 y + 1. What is ab?|a-b|?

11

π2\dfrac{\pi}{2}

22

1+π\sqrt{1+\pi}

1+π1 + \sqrt{\pi}

Answer: C
Concepts:completing the squarequadratic
Difficulty rating: 1140
Solution:

Substitute x=πx=\sqrt{\pi}. Then x2=πx^2=\pi and x4=π2x^4=\pi^2, so the equation becomes y22πy+π2=1.y^2-2\pi y+\pi^2=1.

Hence (yπ)2=1(y-\pi)^2=1, giving the two possible values y=π+1y=\pi+1 and y=π1y=\pi-1. Their distance is 22.

Thus, C is the correct answer.

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