2014 AMC 10A Problem 25

Attempt Problem 25 of the 2014 AMC 10A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2014 AMC 10A solutions, or check the answer key.

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25.

The number 58675^{867} is between 220132^{2013} and 22014.2^{2014}. How many pairs of integers (m,n)(m,n) are there such that 1≤m≤20121\leq m\leq 2012 and 5n<2m<2m+2<5n+1?5^n < 2^m < 2^{m+2} < 5^{n+1}?
278278
279279
280280
281281
282282
Answer: B
Concepts:exponentcounting integers in a rangesystem of equations
Small hint:
Each interval between consecutive powers of 55 contains two or three powers of 22
Big hint:
Use the total number of powers of 22 before 58675^{867}
Solution:
Since 22<5<232^2<5<2^3, each interval (5n,5n+1)(5^n,5^{n+1}) contains either two or three powers of 22. The desired inequality holds exactly for intervals containing three such powers.
For 0≤n<8670\le n<867, let dd be the number of intervals with two powers of 22, and let tt be the number with three powers of 22. Then d+t=867d+t=867.
Because 22013<5867<220142^{2013}<5^{867}<2^{2014}, these intervals contain 20132013 powers of 22 altogether, so 2d+3t=20132d+3t=2013.
Solving the system gives t=279t=279.
Thus, B is the correct answer.
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