2013 AMC 10B Problem 8

Attempt Problem 8 of the 2013 AMC 10B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2013 AMC 10B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

8.

Ray’s car averages 4040 miles per gallon of gasoline, and Tom’s car averages 1010 miles per gallon of gasoline. Ray and Tom each drive the same number of miles. What is the cars’ combined rate of miles per gallon of gasoline?
10 10
16 16
25 25
30 30
40 40
Answer: B
Concepts:rateratio and proportion
Small hint:
Let both cars drive a convenient common distance
Big hint:
Combined miles per gallon is total miles divided by total gallons
Solution:
Let each car drive 4040 miles. Together they drive 8080 miles.
Ray uses 11 gallon, while Tom uses 44 gallons, so together they use 55 gallons.
The combined rate is 80÷5=1680\div5=16 miles per gallon.
Thus, the correct answer is B .
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