2013 AMC 10B Problem 13

Attempt Problem 13 of the 2013 AMC 10B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2013 AMC 10B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

13.

Jo and Blair take turns counting from 11 to one more than the last number said by the other person. Jo starts by saying “11”, so Blair follows by saying “1,1, 22”. Jo then says “1,1, 2,2, 33”, and so on. What number is spoken in position 5353?
2 2
3 3
5 5
6 6
8 8
Answer: E
Concepts:triangular numberpattern recognition
Small hint:
Find the triangular number just before 5353
Big hint:
The next spoken list starts again at 11
Solution:
Through the turn ending with nn, the total number of numbers spoken is 1+2+⋯+n=n(n+1)2. 1+2+\cdots+n=\frac{n(n+1)}2.
After the turn ending with 99, exactly 9⋅102=45\frac{9\cdot10}{2}=45 numbers have been spoken. The next turn is the list 1,2,…,101,2,\ldots,10, so its eighth entry is the 5353rd number spoken. That entry is 88.
Thus, the correct answer is E .
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