2013 AMC 10A Problem 5

Attempt Problem 5 of the 2013 AMC 10A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2013 AMC 10A solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

5.

Tom, Dorothy, and Sammy went on a vacation and agreed to split the costs evenly. During their trip Tom paid $105,\$105, Dorothy paid $125,\$125, and Sammy paid $175.\$175. In order to share costs equally, Tom gave Sammy tt dollars, and Dorothy gave Sammy dd dollars. What is t−d?t-d?
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Answer: B
Concepts:meanmoney
Small hint:
First find the total trip cost and each person’s fair share
Big hint:
Tom and Dorothy each pay Sammy the amount they are short of a fair share
Solution:
The total cost was $105+$125+$175=$405\$105+\$125+\$175=\$405, so each person’s share was $405÷3=$135\$405\div3=\$135.
Tom paid $30\$30 less than his share, and Dorothy paid $10\$10 less than her share, so t=30t=30 and d=10d=10.
Therefore t−d=30−10=20t-d=30-10=20.
Thus, B is the correct answer.
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