2012 AMC 10A Problem 8

Attempt Problem 8 of the 2012 AMC 10A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2012 AMC 10A solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

8.

The sums of three whole numbers taken in pairs are 12,12, 17,17, and 19.19. What is the middle number?
44
55
66
77
88
Answer: D
Concepts:system of equations
Small hint:
Add the three pair sums
Big hint:
The total of the three pair sums is twice the sum of the three numbers
Solution:
Let the three numbers be a,b,ca, b, c where a<b<c.a \lt b \lt c. None of them are equal, since all three sums are different.
Then a+b=12,a+c=17, a + b = 12, a + c = 17, and b+c=19. b + c = 19.
Adding all three equations together gives us 2(a+b+c)=48. 2(a + b + c) = 48.
Then a+b+c=24, a + b + c = 24, from which we can subtract a+c=17, a + c = 17, to get b=7.b = 7.
Thus, D is the correct answer.
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