2011 AMC 10A Problem 15

Attempt Problem 15 of the 2011 AMC 10A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2011 AMC 10A solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

15.

Roy bought a new battery-gasoline hybrid car. On a trip the car ran exclusively on its battery for the first 4040 miles, then ran exclusively on gasoline for the rest of the trip, using gasoline at a rate of 0.020.02 gallons per mile. On the whole trip he averaged 5555 miles per gallon. How long was the trip in miles?
140140
240240
440440
640640
840840
Answer: C
Concepts:ratelinear equation
Small hint:
Let xx be the gasoline-only distance
Big hint:
The miles per gallon equation is x+400.02x=55\frac{x+40}{0.02x}=55
Solution:
Let xx be the distance the car drove solely on gasoline. We have that 40+x0.02x=55. \dfrac{40 + x}{0.02x} = 55. Cross-multiplying and simplifying gives 40=0.1x 40 = 0.1x x=400. x = 400. The total length of the trip is then 400+40=440.400 + 40 = 440.
Thus, C is the correct answer.
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