2011 AMC 10B Problem 15

Below is the professionally curated solution for Problem 15 of the 2011 AMC 10B, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2011 AMC 10B solutions, or check the answer key.

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Concepts:custom operationdistributive property

Difficulty rating: 1280

15.

Let @@ denote the "averaged with" operation: a@b=a+b2.a @ b = \frac{a+b}{2}. Which of the following distributive laws hold for all numbers x,y,x, y, and z?z?

I. x@(y+z)=(x@y)+(x@z)x @ (y + z) = (x @ y) + (x @ z)

II. x+(y@z)=(x+y)@(x+z)x + (y @ z) = (x + y) @ (x + z)

III. x@(y@z)=(x@y)@(x@z)x @ (y @ z) = (x @ y) @ (x @ z)

I only

II only

III only

I and III only

II and III only

Solution:

In text 1, the left hand side equals x+y+z2\dfrac{x+y+z}2 and the right hand side equals x+y+z2,x+ \dfrac{y+z}2, so they aren't equal.

In text 2, the left hand side equals x+y+z2x+ \dfrac{y+z}2 and the right hand side equals x+y+z2,x+ \dfrac{y+z}2, so they are equal.

In text 3, the left hand side equals 2x+y+z4 \dfrac{2x+y+z}4 and the right hand side equals 2x+y+z4,\dfrac{2x+y+z}4, so they are equal.

Thus, the correct answer is E .

Problem 15 in Other Years