2010 AMC 10A Problem 5

Attempt Problem 5 of the 2010 AMC 10A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2010 AMC 10A solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

5.

The area of a circle whose circumference is 24π24\pi is kπ.k\pi. What is the value of k?k?
66
1212
2424
3636
144144
Answer: E
Concepts:circumferencecircle area
Small hint:
Use the circumference to find the radius first
Big hint:
From 2πr=24π2\pi r=24\pi, the desired kk is r2r^2
Solution:
Recall that the formula for the circumference of a circle is 2πr.2 \pi r. We then have that 24π=2πr 24\pi = 2\pi r r=12. r = 12.
The area of a circle is πr2,\pi r^2, so we have that kπ=π122 k \pi = \pi 12^2 k=144. k = 144.
Thus, E is the correct answer.
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