2010 AMC 10A Problem 4

Attempt Problem 4 of the 2010 AMC 10A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2010 AMC 10A solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

4.

A book that is to be recorded onto compact discs takes 412412 minutes to read aloud. Each disc can hold up to 5656 minutes of reading. Assume that the smallest possible number of discs is used and that each disc contains the same length of reading. How many minutes of reading will each disc contain?
50.250.2
51.551.5
52.452.4
53.853.8
55.255.2
Answer: B
Concepts:divisibilityestimation
Small hint:
Determine the minimum number of discs before averaging
Big hint:
77 discs hold too little, while 88 discs suffice
Solution:
Note that 7⋅56=3927 \cdot 56 = 392 and 8⋅56=448,8 \cdot 56 = 448, which means that the minimum number of discs needed is 8.8.
Then the minutes of reading that each disc contains is 412÷8=51.5. 412 \div 8 = 51.5.
Thus, B is the correct answer.
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