2009 AMC 10B Problem 25

Attempt Problem 25 of the 2009 AMC 10B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2009 AMC 10B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

25.

Each face of a cube is given a single narrow stripe painted from the center of one edge to the center of its opposite edge. The choice of the edge pairing is made at random and independently for each face. What is the probability that there is a continuous stripe encircling the cube?
18\dfrac18
316\dfrac{3}{16}
14\dfrac14
38\dfrac38
12\dfrac12
Answer: B
Concepts:basic probabilityindependent eventssymmetry
Small hint:
Each face has 22 equally likely stripe orientations, so 262^6 total configurations
Big hint:
There are 33 possible encircling bands, each fixing the orientation of 44 faces
Solution:
Each face’s stripe has 22 orientations, giving 26=642^6=64 equally likely configurations.
An encircling stripe runs around one of the 33 pairs of opposite faces. For a given band, the 44 faces it crosses must each be oriented to continue it, a probability of (12)4=116.\left(\dfrac12\right)^4=\dfrac{1}{16}.
The three bands are mutually exclusive, so the probability is 3⋅116=316.3\cdot\dfrac{1}{16}=\dfrac{3}{16}.
Thus, the correct answer is B.
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