2009 AMC 10B Problem 24

Attempt Problem 24 of the 2009 AMC 10B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2009 AMC 10B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

24.

The keystone arch is an ancient architectural feature. It is composed of congruent isosceles trapezoids fitted together along the non-parallel sides, as shown. The bottom sides of the two end trapezoids are horizontal. In an arch made with 99 trapezoids, let xx be the angle measure in degrees of the larger interior angle of the trapezoid. What is x?x?
100100
102102
104104
106106
108108
Answer: A
Concepts:regular polygonangle sumsymmetry
Small hint:
Reflect the arch to close it into a full loop of 1818 trapezoids
Big hint:
The inner vertices form a regular 1818-gon; use its interior angle
Solution:
Adding a mirror image completes the arch into a symmetric closed loop of 1818 trapezoids. Their inner edges form a regular 1818-gon, each interior angle of which is (18−2)⋅180∘18=160∘. \dfrac{(18-2)\cdot180^\circ}{18}=160^\circ.
At each inner vertex, two of the trapezoids’ larger angles xx meet the 160∘160^\circ angle around a full turn: x+x+160∘=360∘,x+x+160^\circ=360^\circ, so x=100.x=100.
Thus, the correct answer is A.
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