2008 AMC 10B Problem 8

Attempt Problem 8 of the 2008 AMC 10B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2008 AMC 10B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

8.

A class collects $50\$50 to buy flowers for a classmate who is in the hospital. Roses cost $3\$3 each, and carnations cost $2\$2 each. No other flowers are to be used. How many different bouquets could be purchased for exactly $50?\$50?
11
77
99
1616
1717
Answer: C
Concepts:Diophantine Equationparity
Small hint:
Let rr be the number of roses; then 3r+2c=503r+2c=50
Big hint:
Since 2c2c is even and 5050 is even, rr must be even, and 3r≤503r\le 50
Solution:
If rr roses and cc carnations are bought, then 3r+2c=50.3r+2c=50. Because 2c2c and 5050 are even, 3r3r must be even, so rr is even.
Also 3r≤50,3r\le 50, so r≤16.r\le 16. The even values r=0,2,4,…,16r=0,2,4,\ldots,16 each give a valid c,c, which is 99 bouquets.
Thus, the correct answer is C.
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