2008 AMC 10B Problem 12

Attempt Problem 12 of the 2008 AMC 10B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2008 AMC 10B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

12.

Postman Pete has a pedometer to count his steps. The pedometer records up to 9999999999 steps, then flips over to 0000000000 on the next step. Pete plans to determine his mileage for a year. On January 11 Pete sets the pedometer to 00000.00000. During the year, the pedometer flips from 9999999999 to 0000000000 forty-four times. On December 3131 the pedometer reads 50000.50000. Pete takes 18001800 steps per mile. Which of the following is closest to the number of miles Pete walked during the year?
25002500
30003000
35003500
40004000
45004500
Answer: A
Concepts:place valueunit conversionestimation
Small hint:
Each flip represents 100000100000 steps
Big hint:
Total steps are 44⋅100000+50000,44\cdot 100000+50000, then divide by 18001800
Solution:
Each flip counts 100000100000 steps, so Pete took 44⋅100000+50000=4,450,00044\cdot 100000+50000=4{,}450{,}000 steps.
Dividing by 18001800 gives about 24722472 miles, which is closest to 2500.2500.
Thus, the correct answer is A.
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