2008 AMC 10A Problem 15

Attempt Problem 15 of the 2008 AMC 10A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2008 AMC 10A solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

15.

Yesterday Han drove 11 hour longer than Ian at an average speed 55 miles per hour faster than Ian. Jan drove 22 hours longer than Ian at an average speed 1010 miles per hour faster than Ian. Han drove 7070 miles more than Ian. How many more miles did Jan drive than Ian?
120120
130130
140140
150150
160160
Answer: D
Concepts:distance rate and timesystem of equationsalgebraic manipulation
Small hint:
Let Ian drive tt hours at rr miles per hour
Big hint:
Expanding (r+5)(t+1)−rt=70(r + 5)(t + 1) - rt = 70 gives 5t+r=655t + r = 65
Solution:
Let Ian drive tt hours at rate r,r, covering rtrt miles.
Han drove (r+5)(t+1)−rt(r + 5)(t + 1) - rt =5t+r+5=70,= 5t + r + 5 = 70, so 5t+r=65.5t + r = 65.
Jan drove (r+10)(t+2)−rt(r + 10)(t + 2) - rt =10t+2r+20= 10t + 2r + 20 =2(5t+r)+20= 2(5t + r) + 20 =2⋅65+20= 2 \cdot 65 + 20 =150= 150 miles more than Ian.
Thus, the correct answer is D.
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