2008 AMC 10A Problem 12

Attempt Problem 12 of the 2008 AMC 10A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2008 AMC 10A solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

12.

In a collection of red, blue, and green marbles, there are 25%25\% more red marbles than blue marbles, and there are 60%60\% more green marbles than red marbles. Suppose that there are rr red marbles. What is the total number of marbles in the collection?
2.85r2.85r
3r3r
3.4r3.4r
3.85r3.85r
4.25r4.25r
Answer: C
Concepts:percentagealgebraic manipulation
Small hint:
Write the blue and green counts in terms of rr
Big hint:
From r=1.25br = 1.25b we get b=0.8r,b = 0.8r, and g=1.6rg = 1.6r
Solution:
Since r=1.25b,r = 1.25b, the number of blue marbles is b=r1.25=0.8r.b = \dfrac{r}{1.25} = 0.8r.
The number of green marbles is g=1.6r.g = 1.6r.
The total is r+0.8r+1.6r=3.4r.r + 0.8r + 1.6r = 3.4r.
Thus, the correct answer is C.
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