2007 AMC 10B Problem 8

Attempt Problem 8 of the 2007 AMC 10B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2007 AMC 10B solutions, or check the answer key.

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8.

On the trip home from the meeting where this AMC 10 was constructed, the Contest Chair noted that his airport parking receipt had digits of the form bbcac,bbcac, where 0a<b<c9,0\le a\lt b\lt c\le 9, and bb was the average of aa and c.c. How many different five-digit numbers satisfy all these properties?

1212

1616

1818

2020

2424

Answer: D
Concepts:digitsparitycombinations
Difficulty rating: 1290
Solution:

Once aa and cc are chosen, b=a+c2b=\dfrac{a+c}{2} is determined, and a<b<ca\lt b\lt c holds automatically. For bb to be an integer, aa and cc must share parity.

Choosing two even digits from {0,2,4,6,8}\{0,2,4,6,8\} gives (52)=10\binom{5}{2}=10 pairs, and choosing two odd digits from {1,3,5,7,9}\{1,3,5,7,9\} gives another 10.10.

This yields 2020 valid numbers.

Thus, the correct answer is D.

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