2007 AMC 10B Problem 12

Attempt Problem 12 of the 2007 AMC 10B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2007 AMC 10B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

12.

Tom’s age is TT years, which is also the sum of the ages of his three children. His age NN years ago was twice the sum of their ages then. What is TN?\frac{T}{N}?
22
33
44
55
66
Answer: D
Concepts:ageslinear equation
Small hint:
Express the children’s total age NN years ago in terms of TT and NN
Big hint:
T−N=2(T−3N)T-N=2(T-3N)
Solution:
NN years ago Tom’s age was T−N,T-N, and the sum of his three children’s ages was T−3N.T-3N.
The condition gives T−N=2(T−3N),T-N=2(T-3N), so T−N=2T−6N,T-N=2T-6N, which simplifies to 5N=T.5N=T.
Therefore TN=5.\frac{T}{N}=5.
Thus, the correct answer is D.
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