2006 AMC 10A Problem 5

Attempt Problem 5 of the 2006 AMC 10A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2006 AMC 10A solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

5.

Doug and Dave shared a pizza with 88 equally-sized slices. Doug wanted a plain pizza, but Dave wanted anchovies on half of the pizza. The cost of a plain pizza was $8,\$8, and there was an additional cost of $2\$2 for putting anchovies on one half. Dave ate all the slices of anchovy pizza and one plain slice. Doug ate the remainder. Each then paid for what he had eaten. How many more dollars did Dave pay than Doug?
11
22
33
44
55
Answer: D
Concepts:moneyfraction
Small hint:
A plain pizza costs $8\$8 for 88 slices, so each slice is $1\$1
Big hint:
Dave also pays the full $2\$2 for the anchovies on top of his five slices
Solution:
Each of the 88 slices costs $1.\$1. Dave ate 55 slices and also pays the extra $2\$2 for the anchovies, for a total of 5+2=75 + 2 = 7 dollars.
Doug ate 33 slices, paying 33 dollars. So Dave paid 7−3=47 - 3 = 4 dollars more.
Thus, the correct answer is D.
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