2006 AMC 10A Problem 3

Attempt Problem 3 of the 2006 AMC 10A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2006 AMC 10A solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

3.

The ratio of Mary’s age to Alice’s age is 3:5.3 : 5. Alice is 3030 years old. How many years old is Mary?
1515
1818
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Answer: B
Concepts:ratio and proportionages
Small hint:
Mary’s age is 35\dfrac{3}{5} of Alice’s age
Big hint:
Compute 35⋅30\dfrac{3}{5} \cdot 30
Solution:
Since the ratio is 3:53 : 5 and Alice is 30,30, Mary is 35⋅30=18\dfrac{3}{5} \cdot 30 = 18 years old.
Thus, the correct answer is B.
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