2006 AMC 10A Problem 19

Attempt Problem 19 of the 2006 AMC 10A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2006 AMC 10A solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

19.

How many non-similar triangles have angles whose degree measures are distinct positive integers in arithmetic progression?
00
11
5959
8989
178178
Answer: C
Concepts:angle sumarithmetic sequencecounting integers in a range
Small hint:
If the angles are in arithmetic progression, the middle angle is 60∘60^\circ
Big hint:
The common difference dd satisfies 1≤d≤591 \le d \le 59
Solution:
Let the angles be n−d,n - d, n,n, n+d.n + d. Their sum is 3n=180,3n = 180, so n=60.n = 60.
The measures are distinct positive integers, so d≥1,d \ge 1, and n−d>0n - d \gt 0 forces d<60.d \lt 60. Thus d∈{1,2,…,59},d \in \{1, 2, \ldots, 59\}, giving 5959 non-similar triangles.
Thus, the correct answer is C.
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