2005 AMC 10A Problem 16

Attempt Problem 16 of the 2005 AMC 10A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2005 AMC 10A solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

16.

The sum of the digits of a two-digit number is subtracted from the number. The units digit of the result is 6.6. How many two-digit numbers have this property?

55

77

99

1010

1919

Answer: D
Concepts:digitsplace valueunits digit
Difficulty rating: 1510
Solution:

If the number is 10a+b,10a + b, then (10a+b)(a+b)=9a.(10a + b) - (a + b) = 9a. The units digit of 9a9a is 66 only when a=4,a = 4, since 94=36.9 \cdot 4 = 36. The digit bb can then be anything from 00 to 9,9, giving the ten numbers 4040 through 49.49.

Thus, the correct answer is D.

← Problem 15#15
Full Exam

Problem 16 in Other Years