2005 AMC 10A Problem 13

Attempt Problem 13 of the 2005 AMC 10A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2005 AMC 10A solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

13.

How many positive integers nn satisfy the following condition:
(130n)50>n100>2200? (130n)^{50} \gt n^{100} \gt 2^{200}?
00
77
1212
6565
125125
Answer: E
Concepts:inequalityexponentcounting integers in a range
Small hint:
All quantities are positive, so take the 5050th root of each part of the inequality
Big hint:
The conditions become 130n>n2130n \gt n^2 and n2>16,n^2 \gt 16, which together give 4<n<1304 \lt n \lt 130
Solution:
Taking 5050th roots, the condition becomes 130n>n2>24=16.130n \gt n^2 \gt 2^4 = 16. From n2>16n^2 \gt 16 we get n>4,n \gt 4, and from 130n>n2130n \gt n^2 we get n<130.n \lt 130. So nn ranges over the integers 5,6,…,129,5, 6, \ldots, 129, which is 125125 values.
Thus, the correct answer is E.
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