2004 AMC 10A Problem 13

Attempt Problem 13 of the 2004 AMC 10A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2004 AMC 10A solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

13.

At a party, each man danced with exactly three women and each woman danced with exactly two men. Twelve men attended the party. How many women attended the party?
88
1212
1616
1818
2424
Answer: D
Concepts:double countingcounting pairs
Small hint:
Count the man-woman dancing pairs in two ways
Big hint:
There are 12⋅312 \cdot 3 pairs, and each woman accounts for 22 of them
Solution:
The number of dancing pairs is 12⋅3=36,12 \cdot 3 = 36, counting from the men’s side. Each woman was in exactly 22 pairs, so the number of women is 362=18. \dfrac{36}{2} = 18.
Thus, the correct answer is D.
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