2004 AMC 10A Problem 12

Attempt Problem 12 of the 2004 AMC 10A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2004 AMC 10A solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

12.

Henry’s Hamburger Heaven offers its hamburgers with the following condiments: ketchup, mustard, mayonnaise, tomato, lettuce, pickles, cheese, and onions. A customer can choose one, two, or three meat patties, and any collection of condiments. How many different kinds of hamburgers can be ordered?
2424
256256
768768
40,32040{,}320
120,960120{,}960
Answer: C
Concepts:multiplication principlesubsets
Small hint:
Each of the 88 condiments is independently included or left out
Big hint:
Multiply the 282^8 condiment choices by the 33 choices of patty count
Solution:
Each of the 88 condiments is independently in or out, giving 28=2562^8 = 256 condiment combinations.
For each of these there are 33 choices of patty count, so the number of hamburgers is 3×256=768. 3 \times 256 = 768.
Thus, the correct answer is C.
LIVE by Po-Shen Loh
Programs

LIVE Classes

Self-Paced Classes

Stars

Scholarship

About Us

Who Is Po-Shen Loh?

Email Contact

Newsletter

Jobs

Become a Star

For a more Thought Full world.

© 2026 Expii, Inc.