2004 AMC 10A Problem 12

Attempt Problem 12 of the 2004 AMC 10A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2004 AMC 10A solutions, or check the answer key.

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12.

Henry's Hamburger Heaven offers its hamburgers with the following condiments: ketchup, mustard, mayonnaise, tomato, lettuce, pickles, cheese, and onions. A customer can choose one, two, or three meat patties, and any collection of condiments. How many different kinds of hamburgers can be ordered?

2424

256256

768768

40,32040{,}320

120,960120{,}960

Answer: C
Concepts:multiplication principlesubsets
Difficulty rating: 1190
Solution:

Each of the 88 condiments is independently in or out, giving 28=2562^8 = 256 condiment combinations.

For each of these there are 33 choices of patty count, so the number of hamburgers is 3×256=768. 3 \times 256 = 768.

Thus, the correct answer is C.

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