2003 AMC 10B Problem 12

Attempt Problem 12 of the 2003 AMC 10B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2003 AMC 10B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

12.

Al, Betty, and Clare split $1000\$1000 among them to be invested in different ways. Each begins with a different amount. At the end of one year they have a total of $1500.\$1500. Betty and Clare have both doubled their money, whereas Al has managed to lose $100.\$100. What was Al’s original portion?
$250\$250
$350\$350
$400\$400
$450\$450
$500\$500
Answer: C
Concepts:system of equationsmoney
Small hint:
Let Al, Betty, and Clare start with a,a, b,b, and c,c, so a+b+c=1000a+b+c=1000
Big hint:
The final total is (a−100)+2(b+c)=1500;(a-100)+2(b+c)=1500; substitute b+c=1000−ab+c=1000-a
Solution:
Let a,a, b,b, and cc be the original portions. Then a+b+c=1000a+b+c=1000 and (a−100)+2(b+c)=1500.(a-100)+2(b+c)=1500.
Substituting b+c=1000−ab+c=1000-a into the second equation, a−100+2(1000−a)=1500,a-100+2(1000-a)=1500, so a=400.a=400.
Thus, the correct answer is C.
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